Question 173194
Factor completely:
{{{5x^8-1280}}} First, factor 5 from the binomial.
{{{5(x^8-256)}}}  Notice now that you have the difference of squares:
{{{5(highlight((x^4)^2-(16)^2))}}}...and this can be factored as:
{{{5highlight((x^4-16))(x^4+16)}}}...which can be further factored as:
{{{5highlight((x^2-4))(x^2+4)(x^4+16)}}}...and...
{{{highlight(5(x-2)(x+2)(x^2+4)(x^4+16))}}}