Question 173166
let x=distance she jogged in the 1st night; x+440=distance jogged in the 2nd night; x+880=distance jogged in the 3rd nigth.

x+(x+440)+(x+880)=6600
3x+1320=6600
3x=6600-1320
3x=5280
x=1760

she jogged 1760 yards on the first night.