Question 173138
Note: {{{(f-g)(x)=f(x)-g(x)}}}



So {{{f(x)-g(x)=(5x^2-3x+1)-(x^2+5x-3)=5x^2-3x+1-x^2-5x+3=4x^2-8x+4}}}



This means that {{{f(x)-g(x)=4x^2-8x+4}}}