Question 173087
Find the standard form of the equation of the line that passes through the points (0, -1) and (8, 8).
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I know 2 ways to do this.
One:
Find the slope, m
m = (diff in y)/(diff in x)
m = (8-(-1))/8
m = 9/8
Use either point
y-y1 = m*(x-x1)
y-8 = (9/8)*(x-8
y-8 = 9x/8 - 9
8y - 64 = 9x - 72
9x - 8y = 8
Two:
Use determinants
|x y +1|
|0 -1 1| = 0
|8 +8 1|

x(-1-8) - y(0-8) +(8) = 0
-9x +8y = -8
9x - 8y = 8