<PRE><B>Question 173062</B>
An investor has a total of $26,400 deposited in 3 different accounts, which earn annual interset rates of 6%, 5%, 4%. The amount deposited in the 6% account is twice the amount in the 5% account. If the 3 acccounts earn a total annual nterest of $1331. How much money is deposited in each account?
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Quantity Eq: x    + y     + z     = 26400
Quantity Eq: x    - 2y    + 0     = 0
Interest Eq: 0.06 + 0.05y + 0.04z = 1331 
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solve the system by any means you know to get:
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x = 11000 (amt. invested at 6%)
y = 5500  (amt. invested at 5%)
z = 9900  (amt. invested at 4%)
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Chers,
stan H.</PRE>