Question 172995
A hobby gardner wishes to use 81 ft of fencing to enclose a rectangular gardner and sub divide region into two smaller areas. If the total enclosed is 264 ft squared find the dimensions of the enclosed region. 
-----------------------------------------------------
Draw the picture of the rectangle with a vertical dividing line to create
the two smaller areas.
------------------------
Let the dividing line and 2 parallel sides be of length "x" ft.
-----------
That leaves (81-3x) ft. of fencing for the top and the bottom sides.
Each of those sides will then be (81-3x)/2 ft. in length.
--------------------------------------------------------------
The area will be [(81-3x)/2]*x = 265 sq. ft.
81x - 3x^2 = 530
3x^2 - 81x + 530 = 0
---------------------------------------
x = [81 +- sqrt(81^2 -4*3*530)]/6

x = [81 +- sqrt(201)]6

Positive solution:

x = [81 + 14.18]/6 ft
x = 15.86 ft.
================
Cheers,
Stan H.