Question 172820
Log(2) (x-8) + Log(2) (x+4) = 5
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Assuming you mean log base 2:
{{{log(2,(x-8)) + log(2,(x+4)) = 5}}}
{{{log(2,(x-8)*(x+4)) = 5}}}  Adding logs implies multiplying
(x-8)*(x+4)) = 2^5 = 32
{{{x^2 - 4x - 32 = 32}}}
{{{x^2 - 4x - 64 = 0}}}
*[invoke solve_quadratic_equation 1,-4,-64]
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The negative answer won't work, so it's
2 + 2sqrt(17)