Question 23999
Diregard the other answers I sent to you. I pressed the wrong button.
Start by solving each inequality for y; and put in slope y-intercept form, y=mx+b;
{{{y<=2x+3}}}
y>-x+5
They both are already is in slope intercept form;
The first one;
your y-intercept = 3
secnd one;
y-intercept=5
So what you do on the graph is plot points at your y-intercept; 
Now your first slope=2
second slope=-1
{{{graph (500, 500, -6,6,-6,6, y<=2x+3, y=-x+5)}}}
Now the important part is the shading. since the first eq. is < and = to, you are going to make it a solid line and shade the area BELOW the line.
The second eq.is > so you are going to make the line dotted and shade the area ABOVE the line. 
Hope you understand
=)