Question 172776

First even integer:  {{{n}}}


Next consecutive even integer:  {{{n+2}}}


Sum of the consecutive integers:  {{{n + n + 2=2n+2}}}


Twice the sum:  {{{2(2n+2)=4n+4=260}}}


Solve {{{4n+4=260}}} to get one of the integers, add 2 to the result to get the second one.


Check your work by adding the two integers and doubling the result.  If you get 260, you have done the work correctly.