Question 172742
{{{(3x)^2-(6y)^2}}} since {{{3^2=9}}}and {{{6^2=36}}}we are left with the difference of squares here
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{{{highlight((3x+6y)(3x-6y))}}}factoring
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{{{x^2-15wy+3xy-5wx}}}lets line up the terms that have like variables
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-15wy -5wy)so factor out a -5 and  w  -5w(3y+x)
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{{{x^2+3xy}}}so factor out an x.........x(x+3y)
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do you see any terms that are alike.... that we can factor out of these terms......yes (3y+x)
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so {{{x(x+3y)-5w(x+3y)}}}
factors to
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{{{highlight((x+3y)(x-5w))}}}