Question 172689
2.10000(x+1)(x+1)+3500(x+1)=15569.75------>where x is the interest rate
.... dealing with a quadratic formula.....
when you solve this email me and I will let you know if you have the correct answer.

{{{10000(x^2+2x+1)+3500x+3500=15569.75}}}
:
{{{10000x^2+20000x+10000+3500x+3500=15569.75}}}
:
{{{10000x^2+23500x-2069.75=0}}}
:
drop the negative value{{{system(x=.085,x=-2.64)}}}
:
{{{highlight(x=.085)}}}or 8.5%

*[invoke quadratic "x", 10000, 23500, -2069]