Question 172672
write the expression as a complex number in standard form. 
6i÷1-2i
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6i/(1-2i)
Multiply NUM and DEN by the conjugate, (1+2i)
= 6i*(1+2i)/(1-2i)*(1+2i)
= (6i-12)/(1+4)
= (-12+6i)/5
or -6*(2-i)/5