Question 172670
{{{((6t^2-t-1))/(3(t^2+1))}}}= 2
;
Don't worry about the LCD. Just multiply both sides by 3(t^2+1) to get rid of the denominator:
{{{(6t^2-t-1)}}} = {{{2(3(t^2+1))}}}
:
{{{6t^2-t-1}}} = {{{6t^2+6}}}
:
Variables on the left, numbers on the right
{{{6t^2 - 6^2 - t}}} = 6 + 1
-t = 7
t = -7
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There are no restriction on the domain. Denominator can never = 0
:
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Check this solution by substitution in the original equation