Question 172657
A majority of the club voted to go to a baseball game. They bought 29 tickets. Some of the tickets cost $21 each and some cost $27 each. The total cost of all the tickets was $675. How many tickets if each price did they buy ?
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Quantity Equation: x + y = 29
Value Equation..:21x + 27y = 675
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Adjust to simplify elimination:
21x + 21y = 21*29
21x + 27y = 675
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Subtract 1st from 2nd to solve for "y":
6y = 675 - 21*29
y = 11 (# of $29 tickets)
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Since x + y = 29, x = 18 (# of $21 tickets)

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Cheers,
Stan H.