Question 172548
{{{2^x=32}}} ----->{{{xlog2=log32}}}
{{{x*cross(log2)/cross(log2)=log32/log2}}}
{{{highlight(x=5)}}}
. 
{{{3^(x-2)=81}}} ------>{{{(x-2)log3=log81}}}
{{{(x-2)cross(log3)/cross(log3)=log81/log3}}}
{{{x=4+2=highlight(6)}}}
.
{{{4^x=1/64}}}------->{{{xlog4=log(1/64)}}}
{{{x*cross(log4)/cross(log4)=log(1/64)/log4}}}
{{{highlight(x=-3)}}}
.
Thank you,
Jojo