Question 172456
lets call the amount of metal for the 45% and 70%, a and b respectively
:
a+b=10............eq 1
.45a+.7b=.6(10)...eq 2
:
rewrite eq 1 to b=10-a and plug b's value into eq 2
:
.45a+.7(10-a)=6
:
.45a+7-.7a=6
:
.25a=1
:
{{{highlight(a=4)}}}kg
{{{highlight(b=10-4=6)}}}kg