Question 172448


{{{3x+4y=8}}} Start with the given equation.



{{{4y=8-3x}}} Subtract {{{3x}}} from both sides.



{{{4y=-3x+8}}} Rearrange the terms.



{{{y=(-3x+8)/(4)}}} Divide both sides by {{{4}}} to isolate y.



{{{y=((-3)/(4))x+(8)/(4)}}} Break up the fraction.



{{{y=-(3/4)x+2}}} Reduce.



So the equation {{{y=-(3/4)x+2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-3/4}}} and the y-intercept is {{{b=2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,2\right)]