Question 172419


{{{x^2-18x+32=0}}} Start with the given equation


{{{(x-16)(x-2)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-16=0}}} or  {{{x-2=0}}} 


{{{x=16}}} or  {{{x=2}}}    Now solve for x in each case



So our answers are 


 {{{x=16}}} or  {{{x=2}}}