Question 172432
{{{(z^3+64)/(z^3-4z^2+16z)}}} Start with the given expression



{{{((z+4)(z^2-4z+16))/(z^3-4z^2+16z)}}} Factor the numerator through the use of the sum of cubes formula



{{{((z+4)(z^2-4z+16))/(z(z^2-4z+16))}}} Factor out the GCF "z" from the numerator



{{{((z+4)highlight((z^2-4z+16)))/(z*highlight((z^2-4z+16)))}}} Highlight the common terms.



{{{((z+4)cross((z^2-4z+16)))/(z*cross((z^2-4z+16)))}}} Cancel out the common terms.



{{{(z+4)/z}}} Simplify



So {{{(z^3+64)/(z^3-4z^2+16z)}}} simplifies to {{{(z+4)/z}}}