Question 172192
<pre><font size = 4 color="indigo"><b>
The determinant of matrix {{{(matrix(2,2,A,B,C,D))}}} is writen
just like the matrix except it is enclosed within vertical bars
instead of parentheses or brackets:

{{{abs(matrix(2,2,A,B,C,D))}}}

The rule for finding the value of the determinant is

{{{abs(matrix(2,2,A,B,C,D))=AD-BC}}}

Therefore, the determinant of

{{{(matrix(2,2,5,2,-3,1))}}}

is 

{{{abs(matrix(2,2,5,2,-3,1))}}} 

and its value is:

{{{abs(matrix(2,2,5,2,-3,1))=(5)(1)-(2)(-3)=(5)-(-6)=5+6=11}}}

Edwin</pre>