Question 172086
{{{(1+(1/(x-1)))/(1+(1/(x^2-1)))}}}.....least common multiple on top is x-1 and on the bottom its {{{x^2-1}}}
:
{{{((x-1+1)/(x-1))/((x^2-1+1)/(x^2-1))}}} now combine terms invert the bottom fraction and multiply remembering that {{{x^2-1}}}=(x+1)(x-1)
:
{{{(cross(x)/cross((x-1)))((x+1)cross((x-1))/x(cross(x^2))))}}}=
:
{{{(x+1)/x}}}