Question 172077
solve log base 2^(x-2)=logbase2^(x-4)
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log2 sqrt(x-2)- log2 sqrt(x-4) = 0

= log2[sqrt(x-2)/sqrt(x-4)] = 0

= sqrt[(x-2)/(x-4)] = 2^0

Square both sides to get:
[(x-2)/(x-4)] [(x-2)/(x-4)]  =1
x-2 = x-4
-2 = -4
A contradiction.
No solution for the original equation.
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Cheers,
Stan H.