Question 172069
simplify
(3+3i)/(5+2i)
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These are always done by multiplying the NUM and DEN by the conjugate of the DEN.  The DEN here is 5+2i, so the conjugate is 5-2i.
(3+3i)/(5+2i)
=[(3+3i)*(5-2i)]/[(5+2i)*(5-2i)]
= (15-6i+15i+6)/(25+4)
= (21 + 9i)/29