Question 172047
log(z^2-25)-log(z+5)=log7 
The farthest I got was to re-write the problem to: log(z^2-25)(z+5)=7
-------------
log(z^2-25)-log(z+5)=log7 
log((z-5)*(z+5)) - log(z+5) = log(7) Factor z^2-25
log(z-5) + log(z+5) - log(z+5) = log(7) Add logs when multiplying
log(z-5) = log(7)
z-5 = 7
z = 12