Question 171926

A.  {{{A=(pi)r^2}}}

6in{{{A=(pi)3^2}}}={{{9(pi)}}}sq inches
8in {{{A=(pi)4^2}}}={{{16(pi)}}}sq inches
10in{{{A=(pi)5^2}}}={{{25(pi)}}}sq. inches
:
price per sq in:
:
6in {{{9(pi)/8=9(pi)/8=highlight(1.125(pi))}}}per sq in
8in {{{16(pi)/12=4(pi)/3=highlight(1.33(pi))}}}per sq in
10in{{{25(pi)/20=5(pi)/4=highlight(1.25(pi))}}}per sq in
:
{{{6}}} inch pie gives you the most bang for your buck

:
B. let T be total cost of pie, C= cost / sq in
:
{{{C=(pi)r^2/T}}}.......where r is the radius of the pie
:
{{{(pi)r^2-TC=0}}}