Question 171896
Can someone put me on the right track I came up with 3 solution and I don't think my answer is right please help thank you.. 
Determine whether the following equation have a solution or not? please justify the answer. 
(3)1/2 y^2 - 4y -7 (3)1/2 = 0 
It's not clear what you mean.  What is  "-7 (3)1/2"?
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And can you show me on this one too thank you so much 
z^2 + z + 1 = 0 
*[invoke solve_quadratic_equation 1,1,1]
The solver uses x, not z, just sub for x.
There are no "real" solution, only complex numbers.
z = -1/2 + sqrt(-3)/2
z = -1/2 - sqrt(-3)/2