<PRE><B>Question 24036</B>
Please see my THREE lesson plans in algebra.com in the graphing topic.


In this case, the equation is in standard form, so I recommend you find the intercepts:


2x+3y = 6


If x = 0, then 3y = 6, so y = 2
If y =0, then 2x = 6, so x= 3


Graph these two points, and connect the points with a line.  It should look like this:


{{{graph(300,300,-6,6,-6,6, (6-2x)/3 )}}}


R^2 at SCC  </PRE>