Question 171735
Al and Rudy each roll ordinary dice once. What's the probability that the number of Ruby's roll is greater than the number of Al's roll?
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Generate a sample space: a 6 by 6 pairing of possible results.
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Count the number of pairs where Ruby's roll is greater than Al's.
Form the probability fraction.
I get 15/36 = 5/12
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Cheers,
Stan H.