Question 171627
Add/subtract:
{{{(5/x)-(4/(x+1))+(5/(x^2+x))}}} To add/subtract fractions, you need to find the LCD (Lowest Common Denominator), which, in this case, is {{{x^2+x = x(x+1)}}}, so you would multiply the first fraction by {{{(x+1)/(x+1)}}}, and the second fraction by {{{x/x}}} to get:
{{{(5(x+1))/(x(x+1))-(4x/x(x+1))+(5/(x(x+1)))}}} which simplifies to:
{{{(5x+5-4x+5)/(x(x+1))}}} which further simplifies to:
{{{(x+10)/(x(x+1))}}} or {{{highlight((x+10)/(x^2+x))}}}