<PRE><B>Question 171632</B>
A rope 100 feet long is stretched around four posts set at the corners of a rectangle whose area is 576 square feet. Find the dimensions of the rectangle.
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Perimeter = 2L + 2W = 100
Area = L*W = 576
2L + 2W = 100
L+W = 50
L = 50-W
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A = L*W = (50-W)*W
576 = 50W - W^2
W^2 - 50W + 576 = 0
*[invoke solve_quadratic_equation 1,-50,576]
W = 18, L = 32





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