Question 171634
Find the number of degrees in each angle of a triangle if the first angle is twice the second and three times the third in value.

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The total measure of the angles in any triangle = 180 degrees.

Each triangle has 3 angles.

Here are the 3 angles:

first angle = 2x

second angle = x

third angle = 3x

2x + x + 3x = 180

6x = 180

x = 180/6

x = 30

Now, replace x with 30 for each given angle.

first angle = 2x = 2(30) = 60

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second angle = x = 30

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third angle = 3x = 3(30) = 90

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