Question 171594
    what would log3 28 be

log3 28 = log(28)/log(3) = 1.4472/0.4771 = 0.6905

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    use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.

since we can rewrite
log6 45 = log6(5*3*3)
log6 45 = log6(5) + log6(3) + log6(3)
log6 45 = 0.898244 + 0.1613147 + 0.1613147 = 1.2208734