Question 171594
what would log3 28 be 
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{{{log(3,28) = ln(28)/ln(3)}}} (or log base 10, just so they match)
{{{log(3,28)}}} =~ 3.0331
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and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
45 = 3*3*5
{{{log(6,45) = 2*log(6,3)+log(6,5)}}}
{{{log(6,45) = 2*0.1613147 + 0.898244}}}
{{{log(6,45) = 1.2208734}}} or it would if {{{log(6,3) = 0.1613147}}}  
It doesn't.
{{{log(6,3) = 0.613147}}}  
That makes the {{{log(6,45) = 2.1245388}}}