Question 171587
3x^2+5x-2/3x^2-10x+3 * 2x^2-7x+3/2x^2+3x-2
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There's some ambiguity, but I'll treat it as 2 major fractions.  You should use parentheses, they're free.
{{{((3x^2+5x-2)/(3x^2-10x+3)) * ((2x^2-7x+3)/(2x^2+3x-2))}}}
Factor all trinomials.  
={{{((3x-1)*(x+2)/((3x-1)*(x-3))) * (((2x-1)*(x-3))/((2x-1)*(x+2)))}}}
Cancel where possible
={{{((x+2)/((x-3))) * (((x-3))/((x+2)))}}}
It all cancels, so
= 1