Question 171583
 I need help solving this quadratic equation by factoring:
t(3t+1)=2
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t(3t+1)=2
3t^2 + t = 2
3t^2 + t - 2 = 0  Always get it into this form.  Well, almost always.
(t + 1)*(3t - 2) = 0
Either (t+1) = 0, or
(3t-2) = 0
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t = -1
or t = 2/3