Question 171548
I take a little different approach. First I define the
cost per pound of the ingredients. Then I use those
definitions to define the cost of the mixture.
In words:
(price/pound of 121 nuts)(pounds of 121 nuts) +
(price/pound of 330 nuts)(pounds of 330 nuts) = price of mixture
Let {{{n}}}= pounds of 330 nuts needed
{{{n + 3}}}= pounds of mixture
{{{2.23*3 + 1.75n = 1.93*(n + 3)}}}
{{{6.69 + 1.75n = 1.93n + 5.79}}}
{{{.18n = .9}}}
{{{n = 5}}}
5 pounds of 330 nuts are needed
If you understand this formula, you can always make
a table out of it