Question 2930
 
   {{{x^2+6x+5}}} = 0
 
   = {{{x^2+1x+5x+5}}} = 0  
 
   = {{{x(x+1) + 5(x+1)}}} = 0
 
   = (x+1)(x+5) = 0
  
   so as per the equation, 
 
   either (x+1) = 0 or (x+5) = 0
 
   So x = -1  or x = -5. 
 
   The solution set is {-1, -5}.   Answer
  
  
   It is always not necessary to use the formula to solve such problems.  It   
   can be factorised as above and find out the solution set unless you are     
   asked to solve by using the formula.
 
 
 
 


   gsm