Question 171485
{{{(x-8)/(x^2-x)}}}  denominator of fraction cannot be equal to 0
then x^2-x cannot be 0
lets check when it is = 0 
x^2-x=0
x(x-1)=0
x=0 or x=1
then restricted values are 0 and 1 , it means that this expression is valid for all x except x=0 and x=1