Question 171490
first lets invert and multiply..(we are inverting the{{{(x^2-5x+25)/(x-5)}}}term
:
lets factor certain terms such as the sum of cubes and the difference of cubes 
:
{{{x^3+5^3}}}=(x+5)(x^2-5x+25)
:
{{{x^3-5^3}}}=(x+5)(x^2+5x+25)...with that info lets begin
:
{{{(x+5)cross((x^2-5x+25))cross((x-5))/(cross((x-5))(x^2+5x+25)cross((x^2-5x+25)))}}}
:
{{{highlight((x+5)/(x^2+5x+25))}}}