Question 171429
{{{y = (-3/7)x-2}}} has a {{{Slope=m[1]=(-3/7)}}}
Now, the line in question has a slope , {{{m[2]=m[1]}}}
{{{m[2]=-3/7}}}
then thru points (-4,-3):
following Slope-Intercept form:
{{{y=mx+b}}}
{{{-3=(-3/7)(-4)+b}}}
{{{-3=(12/7)+b}}}
{{{b=-3+(-12/7)=(-21-12)/7=-33/7}}}, Y-intercept
So therefore, {{{highlight(y=(-3/7)x-(33/7))))}}}, ANSWER
Let's see the graph:
{{{drawing(300,300,-10,10,-8,10,grid(1),graph(300,300,-10,10,-8,10,(-3/7)x-2,(-3/7)x-(33/7)),blue(circle(-4,-3,.19))))}}} -----> RED, {{{y=(-3/7)x-2}}} , GREEN, {{{y=(-3/7)x-(33/7)}}} passing thru points (-4,-3),

.
Thank you,
Jojo