Question 171363
This is a "systems of linear equations" problem, but that's ok.




{{{y=2x+6}}} Start with the second equation



{{{4x=2x+6}}} Plug in {{{y=4x}}} (the first equation). What's going on here is we're simply replacing "y" with "4x". This is where the "substitution" comes in.



{{{4x-2x=6}}} Subtract {{{2x}}} from both sides.



{{{2x=6}}} Combine like terms on the left side.



{{{x=(6)/(2)}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



{{{x=3}}} Reduce.



So the first part of the answer is {{{x=3}}} 




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{{{y=4x}}} Go back to the first equation.



{{{y=4(3)}}} Plug in {{{x=3}}} (the previous solution)



{{{y=12}}} Multiply



So the second part of the answer is {{{y=12}}} 



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Answer:



So the solutions are {{{x=3}}} and {{{y=12}}} which form the ordered pair (3,12)