<PRE><B>Question 171334</B>
Find the cos (theta) if csc theta) = 11 square root of 2 divided by 12
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General Form: csc(theta) = r/y
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Your Problem:
csc(theta) = [11sqrt(2)]/12 , so  r = 11sqrt(2) and y = 12
Find x: x = sqrt(r^2-y^2) = sqrt[121*2 + 144] = sqrt(386)
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Since cos(theta) = x/r, cos(theta) = sqrt(386)/11sqrt(2) = sqrt(193)/11
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Cheers,
Stan H.</PRE>