Question 171311
f(x) = {{{-2*x^3 + x^2 + 23}}}
is what i think you said.
no matter.
the procedure is the same.
if
f(x) = {{{-2*x^3 + x^2 + 23}}}
then,
in order to find f(2), you have to substitute (2) for (x) in the equation.
your equation starts out as:
f(x) = {{{-2*x^3 + x^2 + 23}}}
you substitute (2) for (x) to get:
f(2) = {{{-2*(2)^3 + (2)^2 + 23}}}
simplify:
f(2) = {{{-2*(8) + 4 + 23}}}
f(2) = {{{-16 + 4 + 23}}}
f(2) = 11
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if i didn't get your equation right, just follow the same procedure and you'll get your answer.
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