Question 171147
The first equation is a circle with radius 6 and the center is at (-2,4)

(x+2)^2 + (y-4)^2 = 36

The general equation is x^2+y^2= (radius)^2

This is a parabola
y=3x^2 

*[invoke quadratic "x", 3, 0, 0]

This is also a parabola
y=x^2+x

*[invoke quadratic "x", 1, 1, 0]



This is also an equation for a circle
(x-1)^2 + (y-8)^2 = 16
 The center is at (1,8) and the radius is 4.

I hope that this helps!