Question 171134
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Given: {{{x=(-2/7)y+3/4}}}
To get going, we go to the Point-Slope intercept form eqn: {{{y=mx+b}}}
where ---->{{{system(m=Slope, b=yIntercept)}}}
Re-arranging given eqn to follow point-Slope form:
{{{x-(3/4)=(-2/7)y}}}
{{{(x-(3/4))/(-2/7)=cross(-2/7)y/cross(-2/7)}}}
{{{(x/(-2/7))-((3/4)/(-2/7))=y}}}
{{{y=(-7/2)x+(3/4)(7/2)}}} ---->{{{highlight(y=(-7/2)x+(21/8))}}}, ANSWER
So we find that --->{{{system(Slope=m=-7/2,b=yIntercept=21/8)}}}
Going back to given:
{{{f(y)=0}}}
{{{x=(-2/7)(0)+3/4}}}, 
{{{x=3/4}}} ---> X-intercept
See graph:
{{{drawing(300,300,-5,5,-5,5,grid(1),graph(300,300,-5,5,-5,5,(-7/2)x+(21/8)),circle(0,21/8,.15),circle(3/4,0,.15)))}}} ---> see x & y-intercept (3/4,0) & (0,21/8)
.
{{{y= 2x+4}}} ----> It follows Slope Intercept form {{{y=mx+b}}}
{{{f(y)=0}}}
 {{{2x=-4}}} -->{{{cross(2)x/cross(2)=cross(-4)2/cross(2)}}}
{{{highlight(x=-2)}}}, x intercept
{{{f(x)=0}}}
{{{highlight(y=4)}}}, y-intercept
{{{y= -2x-4}}}?
{{{f(y)=0}}}
{{{-2x=4}}} ---> {{{cross(-2)x/cross(-2)=cross(4)2/cross(-2)}}}
{{{highlight(x=-2)}}}, x-intercept
{{{f(x)=0}}}
{{{highlight(y=-4)}}}, y-intercept
see the graph below:
{{{drawing(300,300,-7,7,-7,7,grid(1),graph(300,300,-7,7,-7,7,2x+4,-2x-4),red(circle(0,4,.20)),green(circle(0,-4,.20)),circle(-2,0,.20))}}} ---> RED Line,{{{y=2x+4}}}; GREEN Line, {{{y=-2x-4}}}
Thank you,
Jojo</pre>