Question 171030
Solve for x:
First, you ought to use parentheses to show that the exponent is (x+5).
{{{4^(x+5) = 6}}} Take the logarithm of both sides.
{{{log(4)^(x+5) = log(6)}}} Apply the power rule to the left side.
{{{(x+5)*log(4) = log(6)}}} Divide both sides by {{{log(4)}}}
{{{x+5 = (log(6))/log(4)}}} Evaluate the right side. 
{{{x+5 = 1.29248}}} Subtract 5 from both sides.
{{{x = -3.70752}}}
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At first, because you have no parentheses in 4^x+5 = 6, I assumed that the problem was:
{{{4^x + 5 = 6}}} If this is what you really meant to write, then: Subtract 5 from both sides.
{{{4^x = 1}}} Take the log of both sides.
{{{log(4^x) = log(1)}}} Apply the power rule to the left side.
{{{x*log(4) = log(1)}}} Divide both sides by {{{log(4)}}}
{{{x = (log(1))/log(4)}}} But {{{log(1) = 0}}}, so...
{{{x = 0}}}
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