Question 170959
{{{4x+3y=9}}}, EQN 1 --->{{{y=(-4x+9)/3=(-4/3)x+3}}}, for graph purposes
{{{3y+6=x}}}, EQN 2 ---> {{{y=(x-6)/3=(1/3)x-2}}}, for graph puposes
Subst EQN 1 in EQN 2:
{{{4(3y+6)+3y=9}}}
{{{12y+24+3y=9}}}
{{{15y=9-24=-15}}} -------> {{{cross(15)y/cross(15)=cross(-15)1/cross(15)}}}
{{{highlight(y=-1)}}}, subst. in EQn 2:
{{{3(-1)+6=x}}}
{{{highlight(x=3)}}}
.
Let' see in the graph:
{{{drawing(300,300,-5,5,-5,5,grid(1),graph(300,300,-5,5,-5,5,(-4/3)x+3,(1/3)x-2),blue(circle(3,-1,.15))))}}} ----> see line intersect at points (3,-1); EQN 1>>>RED Line; EQN 2>>>> GREEN Line
.
Thank you,
Jojo