<PRE><B>Question 170990</B>
Find 5 consecutive odd integers such that the sum of the first and the fifth is one less than 3 times the fourth.
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
5th: 2x+5
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EQUATION:
2x-3 + 2x+5 = 3(2x+3)-1
4x+2 = 6x+6
2x = -4
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1st: -7
2nd: -5
etc.
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Cheers,
Stan H.
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