Question 170884
{{{sqrt(16a^4b^6)/sqrt(64(2)a^6b^6)}}}
:
{{{4a^2b^3/8a^3b^3sqrt(2)}}}now multiply top and bottom by {{{sqrt(2)}}} and the radical square root 2 will equal 2 which you multiply by 8 in the denominator
:
{{{4sqrt(2)a^2b^3/16a^3b^3}}} we need to cancel out some terms

{{{cross(4)sqrt(2)cross(a^2)cross(b^3)/4cross(16)(a)cross(a^3)cross(b^3)}}}
:
{{{highlight(sqrt(2)/4a)}}}