Question 170865
{{{y=x^2+x-5}}} Start with the given equation.



Notice we have a quadratic equation in the form of {{{y=ax^2+bx+c}}} where {{{a=1}}}, {{{b=1}}}, and {{{c=-5}}}



Since {{{a>0}}}, which means that "a" is positive, this means that the parabola opens upwards and that the function has a minimum.